x^2=62+2x

Solution for x^2=62+2x equation:

x^2=62+2x

We move all terms to the left:

x^2-(62+2x)=0

We add all the numbers together, and all the variables

x^2-(2x+62)=0

We get rid of parentheses

x^2-2x-62=0

a = 1; b = -2; c = -62;
Δ = b2-4ac
Δ = -22-4·1·(-62)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6\sqrt{7}}{2*1}=\frac{2-6\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6\sqrt{7}}{2*1}=\frac{2+6\sqrt{7}}{2}
$